Q :
²log 8 + ²log 16 = ...
³log 27 = ...
²log 4 = ...![]()
²log 8 + ²log 16 = ...
³log 27 = ...
²log 4 = ...
²log 8 + ²log 16
= ²log 2³ + ²log 16
= 3 × ²log 2 + ²log 16
= 3 × 1 + ²log 16
= 3 + ²log 16
= 3 + 4 × ²log 2
= 3 + 4 × 1
= 3 + 4
= 7
³log 27
= 3 log 3³
= 3 ³log 3
= 3 × 1
= 3
²log 4
= 2 × ²log 2
= 2 × 1
= 2
⃢~ Opung~⃠⃫⃟⃤᳗᳐
²log 8 + ²log 16
²log 2³ + ²log 4²
( 3 × 1 ) + ( 4 × 1 )
3 + 4
7
_______________
³log 27
³log 3³
( 3 × 1 )
3
_______________
²log 4
²log 2²
2 × 1
2
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